Question

М=6*10^21, R=6400 км найти g

Answer 1

g=G*M/R^2

g=6,67*10^-11*6*10^21/6400

g=6,25312*10^7 м/c^2

Answer 2

Ответ:

9,7м/с

Объяснение:

g = $\frac{GM}{R^{2} }$

G = 6,67×10^-11

g = 6,67×10^-11×6×10^21 / 6400^2 = 9,7м/с

Answer 3

To find the acceleration due to gravity (g) at the surface of the Earth, we can use the formula:

$g = \frac{G \cdot M}{R^2}$

where:

• $G$ is the gravitational constant ($G \approx 6.67430 \times 10^{-11} \, \text{m}^3 \, \text{kg}^{-1} \, \text{s}^{-2}$)
• $M$ is the mass of the Earth
• $R$ is the radius of the Earth

Given that the mass of the Earth $M = 6 \times 10^{21}$ kg and the radius of the Earth $R = 6400$ km $= 6400 \times 10^3$ meters, we can calculate $g$ as follows:

$g = \frac{6.67430 \times 10^{-11} \times 6 \times 10^{21}}{(6400 \times 10^3)^2}$

First, let's simplify the values inside the brackets:

$g = \frac{6 \times 6.67430 \times 10^{21} \times 10^{-11}}{(6400 \times 10^3)^2}$

$g = \frac{40.0458 \times 10^{10}}{40960000}$

Now, divide to get the final value of $g$:

$g \approx 9.798 \, \text{m/s}^2$

Therefore, the acceleration due to gravity at the surface of the Earth is approximately $9.798 \, \text{m/s}^2$.