Question

Q1=2,7 * 10\-8 кл q2=3,5*10\-7 кл r=2мм F-?

Answer 1

Ответ:

42,525Н

Объяснение:

Закон Кулона:F=k*q1*q2/r²

k=9*10^9

F=9*10^9*2,7*10^-8*3,5*10^-7/2*10^-6=42,525Н

Answer 2

To calculate the force (F) between two point charges (q1 and q2) separated by a distance (r), we can use Coulomb's law, which is given by:

$F = \frac{k \cdot |q1 \cdot q2|}{r^2}$

where:

• $k$ is Coulomb's constant, approximately $8.99 \times 10^9 \, \text{N m}^2/\text{C}^2$
• $|q1 \cdot q2|$ is the absolute value of the product of the magnitudes of the charges.

Let's plug in the values and calculate the force (F):

Given:

• $q1 = 2.7 \times 10^{-8}$ C (coulombs)
• $q2 = 3.5 \times 10^{-7}$ C (coulombs)
• $r = 2$ mm $= 2 \times 10^{-3}$ m (meters)

Now, calculating the force:

$F = \frac{8.99 \times 10^9 \times |2.7 \times 10^{-8} \times 3.5 \times 10^{-7}|}{(2 \times 10^{-3})^2}$

$F = \frac{8.99 \times 10^9 \times 9.45 \times 10^{-15}}{4 \times 10^{-6}}$

$F = \frac{8.48855 \times 10^{-5}}{4 \times 10^{-6}}$

$F = 21.22138 \, \text{N}$

So, the magnitude of the force (F) between the two charges is approximately 21.22 Newtons.