Question

1. Какое количество теплоты потребляет в сутки Жилой дом, если за это время в отопительную систему дома поступает 1600 кг воды при температуре 90 °С, а уходит она из дома при температуре 50°C ?​

Answer 1

Ответ:

Розв'язок задачі прикріплений нижче.

Объяснение:

Answer 2

Calculation of Heat Consumption in a Residential House

To calculate the amount of heat consumed by a residential house in a day, we need to use the formula:

Q = m * c * ΔT

Where: - Q is the heat energy consumed (in joules or calories) - m is the mass of water (in kilograms) - c is the specific heat capacity of water (in joules per kilogram per degree Celsius or calories per gram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

In this case, the mass of water entering the heating system of the house is 1600 kg, the initial temperature is 90°C, and the temperature when it leaves the house is 50°C.

Let's calculate the heat consumption:

Step 1: Convert the mass of water to grams: - 1 kg = 1000 grams - Therefore, 1600 kg = 1600 * 1000 grams = 1,600,000 grams

Step 2: Calculate the change in temperature: - ΔT = 90°C - 50°C = 40°C

Step 3: Look up the specific heat capacity of water: - The specific heat capacity of water is approximately 4.18 joules per gram per degree Celsius or 1 calorie per gram per degree Celsius.

Step 4: Calculate the heat consumption: - Q = m * c * ΔT - Q = 1,600,000 grams * 4.18 joules/gram/°C * 40°C - Q = 267,520,000 joules

Therefore, the residential house consumes approximately 267,520,000 joules of heat energy in a day.

Please note that this calculation assumes that all the heat energy is transferred from the water to the house, and there are no other factors affecting the heat consumption.