Question

тело движется с начальной скоростью 30 м/с по горизонтальной поверхности. Сила трения, действующая на тело, равна 10Н, а масса тела - 200г. Определите путь, который тело пройдет до остановки.​

Answer 1

Ответ:

Объяснение:

Дано:

V₀ = 30 м/с

Fтр = 10 H

m = 200 г = 0,2 кг

______________

S - ?

Кинетическая энергия тела:

Eк = m·V₀²/2 = 0,2·30²/2 = 90 Дж

Работа сил трения:

A = Fтр·S = 10·S     Дж

Приравняв, находим:

10·S = 90

S =  90 10 = 9 м

Answer 2

Problem Analysis

We are given the following information: - Initial velocity of the body: 30 m/s - Force of friction acting on the body: 10 N - Mass of the body: 200 g

We need to determine the distance traveled by the body before it comes to a stop.

Solution

To solve this problem, we can use the equations of motion. The equation that relates distance, initial velocity, acceleration, and time is:

s = (v^2 - u^2) / (2a)

where: - s is the distance traveled - v is the final velocity (which is 0 in this case, as the body comes to a stop) - u is the initial velocity - a is the acceleration

To find the acceleration, we can use Newton's second law of motion:

F = ma

where: - F is the force of friction - m is the mass of the body - a is the acceleration

Let's calculate the distance traveled by the body.

Calculation

Given: - Initial velocity (u) = 30 m/s - Force of friction (F) = 10 N - Mass of the body (m) = 200 g = 0.2 kg

Using Newton's second law of motion, we can find the acceleration (a):

F = ma

Substituting the given values:

10 = 0.2a

Solving for a:

a = 10 / 0.2 = 50 m/s^2

Now, we can use the equation of motion to find the distance traveled (s):

s = (v^2 - u^2) / (2a)

Substituting the values: - Final velocity (v) = 0 m/s - Initial velocity (u) = 30 m/s - Acceleration (a) = 50 m/s^2

s = (0^2 - 30^2) / (2 * 50) = -900 / 100 = -9 m

The negative sign indicates that the body moves in the opposite direction of its initial velocity. However, distance cannot be negative, so we take the absolute value:

Distance traveled = |s| = |-9| = 9 m

Therefore, the body will travel a distance of 9 meters before coming to a stop.

Answer

The body will travel a distance of 9 meters before coming to a stop.