Question

ПОМОГИТЕ ПОЖАЛУЙСТА!!! Определи, какое количество нефти расходует лайнер за 4 суток, если мощность двигателей равна 27,4 МВт, а их КПД — 26 %. (Удельная теплота сгорания нефти q=46МДжкг).​

Answer 1

Ответ:

η=A/Q

A=P*t

Q=q*m

m=P*t/(η*q)=32*10^6*259200/(0.25*46*10^6)=721252 кг

Answer 2

Calculation of Oil Consumption by the Liner

To determine the amount of oil consumed by the liner in 4 days, we need to calculate the energy consumed by the engines and then convert it to the mass of oil using the specific heat of combustion of oil.

Given information: - Power of the engines: 27.4 MW - Efficiency of the engines: 26% - Specific heat of combustion of oil (q): 46 MJ/kg

To calculate the energy consumed by the engines, we can use the formula:

Energy consumed = Power * Time

Since the time is given as 4 days, we need to convert it to seconds:

Time = 4 days * 24 hours/day * 60 minutes/hour * 60 seconds/minute

Let's calculate the time first:

Time = 4 * 24 * 60 * 60 seconds

Now, we can calculate the energy consumed:

Energy consumed = 27.4 MW * (Time in seconds)

Next, we need to convert the energy consumed to the mass of oil. We can use the formula:

Energy consumed = Mass of oil * Specific heat of combustion of oil

Rearranging the formula, we get:

Mass of oil = Energy consumed / Specific heat of combustion of oil

Let's calculate the mass of oil:

Mass of oil = (Energy consumed) / (Specific heat of combustion of oil)

Now, let's plug in the values and calculate the result.

Calculation:

Time = 4 * 24 * 60 * 60 seconds

Energy consumed = 27.4 MW * (Time in seconds)

Mass of oil = (Energy consumed) / (Specific heat of combustion of oil)

Using the given values and performing the calculations, we find:

Time = 4 * 24 * 60 * 60 = 345,600 seconds

Energy consumed = 27.4 MW * 345,600 seconds

Mass of oil = (Energy consumed) / 46 MJ/kg

Please note that the specific heat of combustion of oil is given in megajoules per kilogram (MJ/kg).

Let's calculate the result:

Energy consumed = 27.4 MW * 345,600 seconds = 9,484,640,000 MJ

Mass of oil = 9,484,640,000 MJ / 46 MJ/kg

Mass of oil = 206,186,086.96 kg

Therefore, the liner consumes approximately 206,186,086.96 kilograms of oil in 4 days.

Please note that this calculation is based on the given information and assumptions.