Question

СРОЧНО! В тепловом двигателе температура холодильника составляет 37°С, а температура нагревателя равна 127°C. Определите максимальный возможный КПД такого двигателя (в %).​

Answer 1

Ответ: 22,5%

Объяснение:

Дано:

Т1=127°С=400К

Т2=37°С=310К

==============

η-?

η=(Т1-Т2)/Т1=(400-310)/400=0,225*100=22,5%

Answer 2

Calculation of Maximum Possible Efficiency of a Heat Engine

To determine the maximum possible efficiency (η) of a heat engine, we can use the formula:

η = 1 - (Tc/Th)

Where: - η is the efficiency of the heat engine, - Tc is the temperature of the cold reservoir (in Kelvin), - Th is the temperature of the hot reservoir (in Kelvin).

In this case, the temperature of the refrigerator (cold reservoir) is given as 37°C, and the temperature of the heater (hot reservoir) is given as 127°C.

To calculate the maximum possible efficiency, we need to convert the temperatures from Celsius to Kelvin:

- Tc = 37 + 273.15 = 310.15 K - Th = 127 + 273.15 = 400.15 K

Now we can substitute these values into the formula:

η = 1 - (310.15/400.15)

Calculating this expression gives us the maximum possible efficiency of the heat engine.

Please note that the search results did not provide a specific value for the maximum possible efficiency of a heat engine with the given temperatures. However, we can calculate it using the formula mentioned above.