Question

19. Визначити середню квадратичну швидкість молекул кисню, аргону та води при температурі 17 °С. 20. Використовуючи дані з попередньої задачі визначте за якої температури середня квадратична температура газів буде становити 5000 м/с.

Answer 1

Ответ:

думаю что правильно, температура в кило кельвинах

Объяснение:

Answer 2

Calculating the Root Mean Square Speed of Oxygen, Argon, and Water Molecules

To calculate the root mean square speed (rms speed) of gas molecules, we can use the formula:

\[v_{rms} = \sqrt{\frac{3RT}{M}}\]

Where: - \(v_{rms}\) = root mean square speed - \(R\) = gas constant (8.314 J/(mol·K)) - \(T\) = temperature in Kelvin - \(M\) = molar mass of the gas in kg/mol

Let's calculate the rms speed for oxygen, argon, and water molecules at a temperature of 17 °C (290 K).

For oxygen (\(O_2\)): - Molar mass of \(O_2\) = 32 g/mol = 0.032 kg/mol - Using the formula, \(v_{rms}\) for \(O_2\) at 290 K is: \[v_{rms} = \sqrt{\frac{3 \times 8.314 \times 290}{0.032}}\]

For argon (\(Ar\)): - Molar mass of \(Ar\) = 40 g/mol = 0.04 kg/mol - Using the formula, \(v_{rms}\) for \(Ar\) at 290 K is: \[v_{rms} = \sqrt{\frac{3 \times 8.314 \times 290}{0.04}}\]

For water (\(H_2O\)): - Molar mass of \(H_2O\) = 18 g/mol = 0.018 kg/mol - Using the formula, \(v_{rms}\) for \(H_2O\) at 290 K is: \[v_{rms} = \sqrt{\frac{3 \times 8.314 \times 290}{0.018}}\]

Let's calculate these values.

Calculating the Temperature for a Given Root Mean Square Speed

To find the temperature at which the rms speed of gas molecules will be 5000 m/s, we can rearrange the rms speed formula to solve for temperature:

\[T = \frac{Mv_{rms}^2}{3R}\]

Where: - \(T\) = temperature in Kelvin - \(M\) = molar mass of the gas in kg/mol - \(v_{rms}\) = root mean square speed - \(R\) = gas constant (8.314 J/(mol·K))

We can use this formula to find the temperature for which the rms speed of gas molecules will be 5000 m/s.

Let's proceed with the calculations.