Question

Какова сила трения, возникающая при действии горизонтальной силы, равной 5Н, на тело массой 30кг, если коэффициент трения между телом и горизонтальной поверхностью составляет 0,2? Пж срочно

Answer 1

F=nN=nmg=0,2*30*10=60Н
Т.к на тело действует сила, которая меньше Силы трения, то она будет равна прилегающей к телу силе
Ответ: 5Н

Answer 2

Calculation of Frictional Force

To calculate the frictional force, we can use the formula:

Frictional Force = Coefficient of Friction * Normal Force

The normal force is equal to the weight of the object, which can be calculated using the formula:

Normal Force = Mass * Gravity

Given: - Force applied = 5 N - Mass of the object = 30 kg - Coefficient of friction = 0.2

Let's calculate the frictional force step by step:

1. Calculate the normal force: - Gravity is a constant, approximately 9.8 m/s^2. - Normal Force = Mass * Gravity - Normal Force = 30 kg * 9.8 m/s^2

2. Calculate the frictional force: - Frictional Force = Coefficient of Friction * Normal Force - Frictional Force = 0.2 * (30 kg * 9.8 m/s^2)

Now, let's calculate the values:

1. Calculate the normal force: - Normal Force = 30 kg * 9.8 m/s^2 = 294 N

2. Calculate the frictional force: - Frictional Force = 0.2 * 294 N

Therefore, the frictional force, when a horizontal force of 5 N is applied to an object with a mass of 30 kg and a coefficient of friction of 0.2, is approximately 58.8 N.

Please note that the above calculation assumes that the object is on a horizontal surface and that the coefficient of friction remains constant throughout the motion.