Question

сопротивление реостата увеличили в 3 раза, а приложенное к нему напряжение уменьшили в 2 раза. Во сколько раз изменилась сила электрического тока, протекающего через реостат?

Answer 1

Ответ:

Объяснение:

R2 = 3*R

U2 = U/2

I1 = U/R

I2 = U / (2*3*R) = U / 6R

I1 / I2 = (U / R) / (U / 6R) = 6 раз

Сила тока уменьшится в 6 раз.

Answer 2

Calculation of the Change in Electric Current

To determine the change in the electric current flowing through the rheostat, we need to consider the relationship between resistance, voltage, and current. According to Ohm's Law, the current flowing through a circuit is directly proportional to the voltage applied and inversely proportional to the resistance.

Let's assume the initial resistance of the rheostat is R and the initial voltage applied is V. After increasing the resistance by 3 times and decreasing the voltage by 2 times, the new resistance becomes 3R and the new voltage becomes V/2.

Using Ohm's Law, we can express the initial current I as:

I = V / R And the new current I' as:

I' = (V/2) / (3R)

Simplifying the equation, we get:

I' = (1/6) * (V / R)

Therefore, the new current I' is 1/6 times the initial current I.

So, the electric current flowing through the rheostat has decreased by a factor of 1/6.

Conclusion

When the resistance of the rheostat is increased by 3 times and the applied voltage is decreased by 2 times, the electric current flowing through the rheostat decreases by a factor of 1/6.

Please let me know if you need any further clarification.