Question

Ядро 83 внизу 214 вверху Bi испытывает β-распад, при этом образуется элемент Х. Напишите уравнение этого радиоактивного распада. Срочно!

Answer 1

Ответ:

²¹⁴ 83Bi β=⁰ -1e + ²¹⁴-⁰ вверху 83+1 внизу X

Answer 2

Radioactive Decay Equation for the Beta Decay of Element Bi-214

The radioactive decay of element Bi-214 involves beta decay, resulting in the formation of another element, denoted as X. To write the equation for this radioactive decay, we need to determine the atomic number and mass number of the element X.

Bi-214 has an atomic number of 83 and is located at the bottom of the periodic table. The element formed after beta decay is denoted as X and has an atomic number of 83 + 1 = 84. To determine the mass number of element X, we need to consider the conservation of mass and charge during the decay process.

During beta decay, a neutron in the nucleus of Bi-214 is converted into a proton, releasing an electron (beta particle) and an electron antineutrino. This results in an increase of one in the atomic number and no change in the mass number. Therefore, the equation for the radioactive decay of Bi-214 can be written as:

Bi-214 → X + e- + νe

Where: - Bi-214 is the parent isotope (initial element) - X is the daughter isotope (element formed after decay) - e- is the beta particle (electron) - νe is the electron antineutrino

Please note that the specific element denoted as X depends on the atomic number of the parent isotope and the type of decay. In this case, the parent isotope Bi-214 decays via beta decay to form an element with an atomic number of 84.

I hope this helps! Let me know if you have any further questions.