Question

До пружини жорсткість якої 500 Н/м, підвісили тіло, вага якого 5 Н. Яке видовження пружини?​

Answer 1

F=kx

x=F/k

x=5/500=0,01 (H/м)

Answer 2

Calculation of Spring Extension

To calculate the extension of the spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to its extension. The formula for Hooke's Law is:

F = kx

Where: - F is the force applied to the spring (in newtons, N) - k is the spring constant (in newtons per meter, N/m) - x is the extension of the spring (in meters, m)

Given: - k = 500 N/m (spring constant) - F = 5 N (applied force)

We can rearrange the formula to solve for x:

x = F / k

Calculation

Substitute the given values into the formula:

x = 5 N / 500 N/m

x = 0.01 m

So, the extension of the spring is 0.01 meters.