Question

413 г жидкости налили в сосуд, площадь дна которого равна 20см2. определи давление жидкости на дно сосуда. принять g = 9,8 h/кг ответ в Па

Answer 1

Ответ:

2023,7Па

Объяснение:

m =413гр = 0,413 кг

S = 20см2 = 0,002 м2

g = 9,8 H\кг

p-?

Решение:

p = F\S    P = F = mg

p = mg\S  

p = 0,413кг * 9,8 Н\кг \ 0,002 м2  = 4,0768 Н \ 0,002 м2 = 2023,7Па

Answer 2

Calculation of Pressure

To calculate the pressure exerted by the liquid on the bottom of the vessel, we can use the formula:

Pressure = Force / Area

In this case, the force is the weight of the liquid, and the area is the surface area of the bottom of the vessel.

Given: - Volume of liquid = 413 g - Area of the bottom of the vessel = 20 cm² - Acceleration due to gravity (g) = 9.8 m/s²

To find the weight of the liquid, we can use the formula:

Weight = Mass × Acceleration due to gravity

Converting the volume of liquid from grams to kilograms: 413 g = 0.413 kg

Calculating the weight of the liquid: Weight = 0.413 kg × 9.8 m/s² = 4.0474 N

Now, we can calculate the pressure:

Pressure = Weight / Area

Converting the area from cm² to m²: 20 cm² = 0.002 m²

Calculating the pressure: Pressure = 4.0474 N / 0.002 m² = 2023.7 Pa

Therefore, the pressure exerted by the liquid on the bottom of the vessel is approximately 2023.7 Pa.