Question

Кульку штовхнули вгору похилою площиною, надавши швидкості 2 м/с. Визначте швидкість руху кульки через 0,5 с; через 1 с; через 1,5 с після початку руху, якщо прискорення руху кульки 2 м/с². Поясніть результат ПЖПДПЖПЖПЖПЖ, будьте кто то другом, помогите!!!¡!!!!!!!!!!¡!​ ну пожалуйста

Answer 1

Ответ:

1

0

1

Объяснение:

v=2

t1=0.5

t2=1

t3=1.5

a=2

____________

V= V0-at

v1=v-at1=1

v2=v-at2=0

v3=v-at3= -1

Answer 2

I can help you with your physics problem. Here is the detailed solution:

The initial velocity of the ball is 2 m/s. The acceleration of the ball is 2 m/s². The velocity of the ball at any time t is given by the formula:

$$v = v_0 + at$$

where $v_0$ is the initial velocity and $a$ is the acceleration.

To find the velocity of the ball after 0.5 s, we plug in the values of $v_0$, $a$, and $t$ into the formula:

$$v = 2 + 2 \times 0.5$$

$$v = 3 \text{ m/s}$$

To find the velocity of the ball after 1 s, we plug in the values of $v_0$, $a$, and $t$ into the formula:

$$v = 2 + 2 \times 1$$

$$v = 4 \text{ m/s}$$

To find the velocity of the ball after 1.5 s, we plug in the values of $v_0$, $a$, and $t$ into the formula:

$$v = 2 + 2 \times 1.5$$

$$v = 5 \text{ m/s}$$

The result shows that the velocity of the ball increases linearly with time, as expected from the constant acceleration. The ball moves faster as it goes up the inclined plane.