Question

Електропотяг, відходячи зі станції, упродовж 0.5 хв рухався з прискоренням 0.8 м/с. визначте шлях, який він пройшов за цей час, і швидкість у кінці цього шляху ​

Answer 1

0,5мин = 30с

скорость

V=at=0,8.30 = 24м/с = 24-3,6 = 86,4 км/

Путь разгона

S = 0,5at² = 0,5-0,8.30² = 360м

Answer 2

To find the distance traveled by the train and its final velocity, we can use the equations of motion. The equations of motion relate the initial velocity (u), final velocity (v), acceleration (a), time (t), and distance (s). In this case, the train starts from rest (u = 0) and has a constant acceleration of 0.8 m/s² for a time of 0.5 seconds.

Finding the distance traveled:

The equation to find the distance traveled is given by: s = ut + (1/2)at²

Since the initial velocity (u) is 0, the equation simplifies to: s = (1/2)at²

Substituting the given values: s = (1/2)(0.8 m/s²)(0.5 s)²

Calculating the distance: s = (1/2)(0.8 m/s²)(0.25 s²) s = 0.1 m

Therefore, the train traveled a distance of 0.1 meters in 0.5 seconds.

Finding the final velocity:

The equation to find the final velocity is given by: v = u + at

Since the initial velocity (u) is 0, the equation simplifies to: v = at

Substituting the given values: v = (0.8 m/s²)(0.5 s) v = 0.4 m/s

Therefore, the train's final velocity at the end of the 0.5-second interval is 0.4 m/s.

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