Question

З якою силою діє на стіл акваріум об'ємом 50 л, на 4/5 наповнений водою? Густина води 1000 кг/ M3........срочно плиз!!!​

Answer 1

Ответ: 40Н

Объяснение:

Дано

V=4/5*50л=40л=0,04м³

ρ=1000кг/м³

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Р-?

Р=ρVg=1000*0,04*10=400Н

Answer 2

Calculating the Force Acting on the Aquarium Table

To calculate the force acting on the table due to the weight of the water in the aquarium, we can use the formula:

Force = Mass x Acceleration due to gravity

First, we need to calculate the mass of the water in the aquarium.

Calculating the Mass of Water in the Aquarium

The mass of the water can be calculated using the formula:

Mass = Volume x Density

Given: - Volume of water (V) = 4/5 * 50 L - Density of water = 1000 kg/m^3

Let's calculate the mass of the water in the aquarium:

Mass = (4/5 * 50 L) * 1000 kg/m^3

Calculation

The mass of the water in the aquarium is: Mass = (4/5 * 50) * 1000 = 40 * 1000 = 40000 kg

Calculating the Force

Now, we can calculate the force acting on the table due to the weight of the water.

Force = Mass x Acceleration due to gravity

Given: - Acceleration due to gravity (g) = 9.81 m/s^2

Let's calculate the force:

Force = 40000 kg * 9.81 m/s^2

Calculation

The force acting on the table due to the weight of the water in the aquarium is: Force = 40000 kg * 9.81 m/s^2 = 392400 N

So, the force acting on the table due to the weight of the water in the 4/5 filled 50 L aquarium is 392400 N.