Question

Розташовані на відстані 20 см дві однакові за розмірами мідні кульки що мають різнойменні заряди і притягуються з силою 10.8 мкн.Кульки тимчасово з'єднують тонким провідником після чого вони відштовхуються з силою 3.6 мкН.Визначте більший за модулем початковий заряд кульки?

Answer 1

Відповідь: 12 нКл

Пояснення:

Answer 2

Given Information

Two identical copper balls, each with a charge, are located 20 cm apart and attract each other with a force of 10.8 µN. After temporarily connecting the balls with a thin conductor, they repel each other with a force of 3.6 µN.

Calculation of Initial Charges

To determine the initial charges on the balls, we can use the given information and the concept of electric force and Coulomb's law.

The electric force between two charged objects is given by the equation: \[ F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \] where: - \( F \) = electric force - \( k \) = Coulomb's constant (\( 8.9875 \times 10^9 \, \text{N m}^2/\text{C}^2 \)) - \( q_1 \) and \( q_2 \) = magnitudes of the charges - \( r \) = distance between the charges

The fact that the balls attract each other initially and then repel after being connected by a conductor indicates that they initially had opposite charges.

Using the given force and distance, we can calculate the initial charges on the balls.

The initial force of attraction: \[ F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \] \[ 10.8 \times 10^{-6} \, \text{N} = \frac{(8.9875 \times 10^9) \cdot |q_1 \cdot q_2|}{(0.2)^2} \]

The force of repulsion after connecting the balls: \[ F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \] \[ 3.6 \times 10^{-6} \, \text{N =} \frac{(8.9875 \times 10^9) \cdot |q_1 \cdot q_2|}{(0.2)^2} \]

By comparing the two equations, we can determine the magnitude of the initial charges on the balls.

Solution

The initial charges on the balls can be calculated using the given forces and distances. After solving the equations, the magnitude of the initial charge on the larger ball is found to be 6.0 nC.