Question

❗❗❗❗срочно дам 20 балов❗❗❗❗ Яка сила прикладена до тіла масою 50 кг у горизонтальному напрямку, якщо під дією цієї сили тіло рівномірно рухається горизонтальною поверхнею? Коефіцієнт тертя становить 0,3​

Answer 1

Ответ:

150Н.

Объяснение:

u=0,3

m=50кг

a=0м/с²

g=10м/с²

F-?

Fтер=uN=u×m×g=0,3×50×10=150H

F=Fтер=150Н.

Answer 2

To calculate the force applied to a body of mass 50 kg moving uniformly on a horizontal surface with a coefficient of friction of 0.3, we can use Newton's second law of motion. According to this law, the net force acting on an object is equal to the product of its mass and acceleration.

Calculating the force applied:

The force applied can be calculated using the formula: Force = mass x acceleration.

In this case, the body is moving uniformly, which means its acceleration is zero. Therefore, the net force acting on the body is also zero. This implies that the force applied to the body is equal in magnitude but opposite in direction to the force of friction.

Calculating the force of friction:

The force of friction can be calculated using the formula: Force of friction = coefficient of friction x normal force.

The normal force is the force exerted by the surface on the body perpendicular to the surface. In this case, since the body is on a horizontal surface, the normal force is equal to the weight of the body, which can be calculated as: Weight = mass x gravitational acceleration.

The gravitational acceleration is approximately 9.8 m/s^2.

Now, let's calculate the force of friction:

Weight = 50 kg x 9.8 m/s^2 = 490 N

Force of friction = 0.3 x 490 N = 147 N

Therefore, the force applied to the body in the horizontal direction is 147 N.