Question

при деякій напрузі на кінцях провідника сила струму в ньому становить 2А.Чому дорівнює сила струму в цьому провіднику,якщо напругу на кінцях зменшити у 4 рази?​

Answer 1

Ответ:

0,5А

Объяснение:

если сопротивление постоянно, то ток через проводник пропорционален напряжению. так что 2А/4=0,5А

Answer 2

When the voltage across a conductor is reduced by a factor of 4, the current flowing through it can be calculated using Ohm's Law. Ohm's Law states that the current (I) flowing through a conductor is directly proportional to the voltage (V) across the conductor and inversely proportional to the resistance (R) of the conductor. Mathematically, Ohm's Law can be expressed as:

I = V / R

In this case, the current flowing through the conductor is initially 2A when the voltage across it is at a certain level. If the voltage is reduced by a factor of 4, we can calculate the new current using Ohm's Law.

Let's assume that the resistance of the conductor remains constant. Therefore, we can rewrite Ohm's Law as:

I2 = (V2 / R)

Where: - I2 is the new current flowing through the conductor. - V2 is the new voltage across the conductor. - R is the resistance of the conductor.

Since the voltage is reduced by a factor of 4, we can substitute V2 with (V / 4):

I2 = ((V / 4) / R)

Simplifying the equation:

I2 = (V / (4R))

Now, we can substitute the initial current value (2A) and solve for the new current (I2):

2A = (V / (4R))

Multiplying both sides of the equation by (4R):

8AR = V

Therefore, the new current (I2) when the voltage is reduced by a factor of 4 is 8A.

Please note that this calculation assumes that the resistance of the conductor remains constant. If the resistance changes, the relationship between voltage and current may be different.