Question

V=10м/c m-100кг H-5м W-?

Answer 1

Ek=mv^2/2=100*100/2=5000
Ep=mgh=100*10*5=5000
Wtf=Ek+Ep=5000+5000=10000

Answer 2

To solve for the unknown value W, we need to use the principle of conservation of energy.

At the initial state, the body has gravitational potential energy due to its height above the ground, but no kinetic energy because it's at rest:

U_i = mgh = 100 kg * 9.81 m/s^2 * 5 m = 4905 J K_i = 0 J

At the final state, the body has lost its gravitational potential energy because it has fallen to the ground, but gained kinetic energy due to its motion:

U_f = 0 J K_f = (1/2) * m * v^2 = (1/2) * 100 kg * (10 m/s)^2 = 5000 J

The total energy of the system (body + Earth) is conserved, so:

U_i + K_i = U_f + K_f

Solving for W, which represents the work done by the gravitational force on the body during its fall:

W = U_i - U_f = 4905 J - 0 J = 4905 J

Therefore, the work done by the gravitational force on the body during its fall is 4905 Joules.