Question

Q1=-3мкКл q2=6мкКл r=3см k=9*10^9 F-? x-?

Answer 1

Си:
3•10^-6Кл
6•10^-6Кл
0,03м
Решение:
F=kq1q2/r^2
F=9•10^9•3•10^-6•6•10^-6/0,03^2=162•10^-3/0,0009=180Н
Ответ:F=180Н
Надеюсь правильно))
Правда вот «х-?» я не поняла зачем он‍♀️

Answer 2

Using Coulomb's law, the force (F) between two point charges (q1 and q2) separated by a distance (r) can be calculated as:

F = (k * q1 * q2) / r^2

where k is the Coulomb's constant, which is equal to 9 x 10^9 Nm^2/C^2.

Substituting the given values, we get:

F = (9 x 10^9 Nm^2/C^2) * (-3 x 10^-6 C) * (6 x 10^-6 C) / (0.03 m)^2 F = -54 N

Therefore, the force between the two charges is -54 N, which means that the charges are attracting each other.

To find the distance (x) between the two charges at which the force is zero (i.e., the equilibrium point), we can use the following equation:

F = (k * q1 * q2) / x^2

Setting F to zero and solving for x, we get:

x = sqrt((k * q1 * q2) / F) x = sqrt((9 x 10^9 Nm^2/C^2) * (-3 x 10^-6 C) * (6 x 10^-6 C) / (-54 N)) x = 0.15 m

Therefore, the equilibrium distance between the two charges is 0.15 m.