Question

-3(3y+4)+4(2y-1)=0 как решить

Answer 1

To solve the equation -3(3y+4) + 4(2y-1) = 0, we can follow these steps:

Step 1: Distribute the terms inside the parentheses: -3 * 3y = -9y -3 * 4 = -12 4 * 2y = 8y 4 * -1 = -4

The equation becomes: -9y - 12 + 8y - 4 = 0

Step 2: Combine like terms: (-9y + 8y) + (-12 - 4) = 0 -y - 16 = 0

Step 3: Solve for y: To isolate y, we can multiply both sides of the equation by -1: (-1)(-y - 16) = (-1)(0) y + 16 = 0

Subtract 16 from both sides: y + 16 - 16 = 0 - 16 y = -16

Therefore, the solution to the equation -3(3y+4) + 4(2y-1) = 0 is y = -16.

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