Question

Два поезда вышли в разное время навстречу друг другу из двух городов, расстояние между которыми 782км. Скорость первого поезда 52км/ч, а второго 61 км/ч. пройдя 416 км, первый поезд встретился со вторым. На сколько один из поездов вышел раньше другого?

Answer 1

Problem Analysis

We have two trains traveling towards each other from two different cities. The distance between the cities is 782 km. The first train is traveling at a speed of 52 km/h, and the second train is traveling at a speed of 61 km/h. After traveling 416 km, the first train meets the second train. We need to determine how much earlier one train left compared to the other.

Solution

To solve this problem, we can use the formula: time = distance / speed. Let's calculate the time it took for each train to travel the given distance.

The first train traveled 416 km at a speed of 52 km/h. Using the formula, we can calculate the time it took for the first train to travel this distance:

time = distance / speed = 416 km / 52 km/h = 8 hours

Similarly, the second train traveled the same distance of 416 km at a speed of 61 km/h. Using the formula, we can calculate the time it took for the second train to travel this distance:

time = distance / speed = 416 km / 61 km/h ≈ 6.82 hours

Since the two trains met after 8 hours, and the second train took 6.82 hours to cover the same distance, we can conclude that the second train left 1.18 hours (or approximately 1 hour and 11 minutes) later than the first train.

Therefore, one train left approximately 1 hour and 11 minutes earlier than the other train.

Answer

One of the trains left approximately 1 hour and 11 minutes earlier than the other train.