Question

Три ёжика собрали 60 грибов. Они поделили их так: первый взял себе на 10 грибов меньше, а третий – на 10 грибов больше, чем второй. Сколько взял каждый?_________________________________________

Answer 1

Problem Analysis

We are given that three hedgehogs collected a total of 60 mushrooms. The first hedgehog took 10 mushrooms less than the second hedgehog, and the third hedgehog took 10 mushrooms more than the second hedgehog. We need to determine how many mushrooms each hedgehog took.

Solution

Let's assume that the second hedgehog took x mushrooms.

According to the given information: - The first hedgehog took 10 mushrooms less than the second hedgehog, so it took (x - 10) mushrooms. - The third hedgehog took 10 mushrooms more than the second hedgehog, so it took (x + 10) mushrooms.

The sum of the mushrooms taken by all three hedgehogs is 60. Therefore, we can write the equation:

(x - 10) + x + (x + 10) = 60

Simplifying the equation: 3x = 60 x = 20

So, the second hedgehog took 20 mushrooms.

Using this information, we can determine the number of mushrooms taken by the other two hedgehogs: - The first hedgehog took 10 mushrooms less than the second hedgehog, so it took (20 - 10) = 10 mushrooms. - The third hedgehog took 10 mushrooms more than the second hedgehog, so it took (20 + 10) = 30 mushrooms.

Therefore, the first hedgehog took 10 mushrooms, the second hedgehog took 20 mushrooms, and the third hedgehog took 30 mushrooms.

Answer

The first hedgehog took 10 mushrooms, the second hedgehog took 20 mushrooms, and the third hedgehog took 30 mushrooms.