Question

решение к задаче:клетка льва и клетка тигра имеют форму параллелепипеда.У какой клетки площадь пола больше и во сколько раз,если длина клетки льва в 2 раза меньше длины клетки слона,а ширина их клеток одинаковая?

Answer 1

Problem Analysis

We have two cells, one for a lion and one for a tiger, both in the shape of a rectangular parallelepiped. We need to determine which cell has a larger floor area and by how many times, given that the length of the lion's cell is half the length of the elephant's cell, and the width of both cells is the same.

Solution

To solve this problem, we need to compare the floor areas of the lion's cell and the tiger's cell. The floor area of a rectangular parallelepiped is calculated by multiplying the length and width of the base.

Let's assume: - Length of the tiger's cell = L - Length of the lion's cell = L/2 (half the length of the tiger's cell) - Width of both cells = W

The floor area of the tiger's cell is given by: Area of Tiger's Cell = L * W

The floor area of the lion's cell is given by: Area of Lion's Cell = (L/2) * W

To determine which cell has a larger floor area, we can compare the two areas. If the area of the tiger's cell is greater, we can calculate the ratio of the two areas by dividing the area of the tiger's cell by the area of the lion's cell.

Calculation

Let's calculate the floor areas and the ratio.

Area of Tiger's Cell = L * W

Area of Lion's Cell = (L/2) * W

Ratio = Area of Tiger's Cell / Area of Lion's Cell

Answer

The floor area of the tiger's cell is greater than the floor area of the lion's cell. The ratio of the floor areas depends on the specific values of L and W.

Please provide the specific values for the length of the tiger's cell (L) and the width of both cells (W) so that we can calculate the exact ratio.