Question

из пункта а в б одновременно навстречу друг другу выехал велосипедист и вышел пешеход . через какое время они встретятся , если велосипедисту на весь путь 40 мин. а пешеходу 2 ч?

Answer 1

I found some web search results that might help you with your question. Here is a summary of the answer:

- To solve this problem, we need to find the speed of the cyclist and the pedestrian, the distance between A and B, and the time they meet. - The speed of the cyclist is the distance divided by the time. If the cyclist takes 40 minutes to cover the whole distance, then his speed is S/40, where S is the distance between A and B. - The speed of the pedestrian is also the distance divided by the time. If the pedestrian takes 2 hours (or 120 minutes) to cover the whole distance, then his speed is S/120. - The speed of their approach is the sum of their speeds. So, the speed of their approach is S/40 + S/120 = (3S + S)/120 = 4S/120 = S/30. - The time they meet is the distance divided by the speed of their approach. So, the time they meet is S / (S/30) = S * 30/S = 30 minutes.

Therefore, the cyclist and the pedestrian will meet after 30 minutes from the start of their movement.

You can find more details and explanations in the following web search results:

- [Из пунктов A и B одновременно навстречу друг другу выехал велосипедист и вышел пешеход. Через... - ответ на Uchi.ru](https://uchi.ru/otvety/questions/iz-punktov-a-i-b-odnovremenno-navstrechu-drug-drugu-vyehal-velosipedist-i-vyshel-peshehod-e40977ab-bebe-4945-bef8-836be7e0bc0b) - [564. ГДЗ Математика 5 класс Никольский. Помогите посчитать, когда встретятся велосипедисты – Рамблер/класс](https://class.rambler.ru/temy-gdz/564-gdz-matematika-5-klass-nikolskiy-pomogite-poschitat-kogda-vstretyatsya-velosipedisty-59668.htm) - [Из пунктов A и B одновременно навстречу друг другу вышли два пешехода. Они встретились через 40... - ответ на Uchi.ru](https://uchi.ru/otvety/questions/iz-punktov-a-i-b-odnovremenno-navstrechu-drug-drugu-vishli-dva-peshehoda-oni-vstretilis-c-8aebcd43-05a7-4c94-9529-aeabc2679387)

I hope this helps you.