Question

Из города А в город Б, расстояние между которыми 200 км, выехал автобус. Через 1 ч 20 мин вслед за ним выехал автомобиль, скорость которого в 1,5 раза больше скорости автобуса. Найдите скорость автобуса, если в город В они прибыли одновременно.

Answer 1

Problem Analysis

We are given that a bus and a car travel from City A to City B, a distance of 200 km. The car starts 1 hour and 20 minutes after the bus and has a speed that is 1.5 times faster than the bus. We need to find the speed of the bus.

Solution

Let's assume the speed of the bus is x km/h. Since the car's speed is 1.5 times faster than the bus, the speed of the car is 1.5x km/h.

We know that the time taken by both the bus and the car to travel from City A to City B is the same. Let's calculate the time taken by each vehicle.

The time taken by the bus is given by: time taken by bus = distance / speed of bus = 200 / x (in hours)

The time taken by the car is given by: time taken by car = distance / speed of car = 200 / (1.5x) (in hours)

Since both vehicles arrive at City B at the same time, we can set up the following equation:

200 / x = 200 / (1.5x)

To solve for x, we can cross-multiply and simplify the equation:

200 * (1.5x) = 200 * x

Simplifying further:

300x = 200x

Dividing both sides by 200x:

300 = 200

Since this equation is not true, we have reached an inconsistency. This means that there is no solution for the given scenario. It is not possible for the bus and the car to arrive at City B at the same time.

Therefore, we cannot determine the speed of the bus.

Conclusion

Based on the given information, it is not possible to determine the speed of the bus. The scenario described does not have a solution where both the bus and the car arrive at City B at the same time.