Question

Решите уравнение:1)7целых 3/10+25/28×=8целых13/35; 2)3целых1/3-1целая1/20×=1целая14/15; 3)3/8×+7/12×-5/6×=9/32;

Answer 1

$7 \frac{3}{10}+ \frac{25}{28}x=8 \frac{13}{35} \\ \\ \frac{25}{28}x= \frac{293}{35}- \frac{73}{10} \\ \\ \frac{25}{28}x= \frac{586-511}{70} \\ \\ x= \frac{15}{14}* \frac{28}{25} \\ \\ x=1 \frac{1}{5}$

$3 \frac{1}{3}-1 \frac{1}{20}x=1 \frac{14}{15} \\ \\ - \frac{21}{20}x= \frac{29}{15}- \frac{10}{3} \\ \\ - \frac{21}{20}x= \frac{29-50}{15} \\ \\ x=- \frac{21}{15}*(- \frac{20}{21}) \\ \\ x=1 \frac{1}{3}$

$\frac{3}{8}x+ \frac{7}{12}x- \frac{5}{6}x= \frac{9}{32} \\ \\ (\frac{9+14-20}{24})x= \frac{9}{32} \\ \\ \frac{1}{8}x= \frac{9}{32} \\ \\ x= \frac{9}{32}* \frac{8}{1} \\ \\ x=2 \frac{1}{4}$