Question

3(х-8)=2х-4. 3х-2=14-5х. 8(х+2)=5(х+2)+15. 15(х-2)=17 пожалуйста по математике​

Answer 1

Ответ:

Пошаговое объяснение:

3(х-8)=2х-4.

3х-24=2х-4

3х-2х=24-4

х=20

3х-2=14-5х.

3х+5х=14+2

8х=16

х=16:8

х=2

8(х+2)=5(х+2)+15.

8х+16=5х+10+15

8х-5х=10+15-16

3х=9

х=9:3

х=3

15(х-2)=17

15х-30=17

15х=17+30

15х=47

х=47\15=3 2\15

Answer 2

Equation 1: 3(х-8) = 2х-4

To solve this equation, we will simplify and isolate the variable 'x'.

Let's start by distributing the 3 on the left side of the equation: 3 * x - 3 * 8 = 2x - 4 3x - 24 = 2x - 4

Next, let's isolate the variable 'x' by moving all terms with 'x' to one side and the constant terms to the other side: 3x - 2x = 24 - 4 x = 20

Therefore, the solution to the equation 3(х-8) = 2х-4 is x = 20.

Equation 2: 3х-2 = 14-5х

To solve this equation, we will simplify and isolate the variable 'x'.

Let's start by combining like terms on both sides of the equation: 3x + 5x = 14 + 2 8x = 16

Next, let's isolate the variable 'x' by dividing both sides of the equation by 8: x = 16/8 x = 2

Therefore, the solution to the equation 3х-2 = 14-5х is x = 2.

Equation 3: 8(х+2) = 5(х+2) + 15

To solve this equation, we will simplify and isolate the variable 'x'.

Let's start by distributing the 8 and 5 on their respective sides of the equation: 8x + 16 = 5x + 10 + 15 8x + 16 = 5x + 25

Next, let's isolate the variable 'x' by moving all terms with 'x' to one side and the constant terms to the other side: 8x - 5x = 25 - 16 3x = 9

Finally