Question

Поле прямоугольной формы имеет ширину 800м. а длину 2 км. 400 м. Если норма высева пшеницы составляет 240 кг на 1 га, то всего пшеницы требуется высеять. Помогите решить!!!Буду ну очень благодарнаааа!!!

Answer 1

1)2400х800=1920000 м.кв.=192га - площадь поля
2)240х192=46080кг=46,08т=46т80кг.
ответ: всего надо будет высеять 46тонни 80 кг пшеницы

Answer 2

Calculation of Total Wheat Required

To calculate the total amount of wheat required to sow the field, we need to find the area of the field and then multiply it by the seeding rate.

Given: - Width of the rectangular field: 800 m - Length of the rectangular field: 2 km 400 m

To find the area of the field, we can multiply the width by the length. However, since the length is given in kilometers and meters, we need to convert it to meters first.

Converting the length to meters: - 2 km = 2,000 m - 400 m (already in meters)

Adding the converted length to the width: - Total length = 2,000 m + 400 m = 2,400 m

Calculating the area of the field: - Area = Width × Length = 800 m × 2,400 m = 1,920,000 square meters

Now, we need to convert the area from square meters to hectares. Since 1 hectare is equal to 10,000 square meters, we can divide the area by 10,000.

Converting the area to hectares: - Area in hectares = 1,920,000 square meters ÷ 10,000 = 192 hectares

The seeding rate is given as 240 kg per hectare. To find the total amount of wheat required, we can multiply the seeding rate by the area in hectares.

Calculating the total amount of wheat required: - Total wheat required = Seeding rate × Area in hectares = 240 kg/ha × 192 ha

Therefore, the total amount of wheat required to sow the field is 46,080 kg (or 46.08 metric tons).