Question

петя и вася одновременно побежали по кругу. Когда Петя обогнал васю в третий раз,Вася пробежал ровно 6 кругов. ВО сколько раз скорость петВаси, если они бегут с постоянными скоростями. задача 1) задача 2) Я иду от дома до школы за 30 минут,а моя сестра- за 40 минут.Через сколько минут ,я доганю сестру, если я вышел из дома через 5 минут после её ухода.

Answer 1

1) Раз Вася пробезал 6 кругов, а Петя обогнал его 3 раза. То Петя пробежал 6+3=9 кругов за то же время. Тогда скорости относятся как 9:6= 1.5

Ответ: Скорость Пети в 1,5 раз больше Васи. 

2) во вложении.

Answer 2

Problem 1: Петя и Вася бегут по кругу

To solve this problem, we need to determine the ratio of the speeds of Petya and Vasya when Petya overtakes Vasya for the third time.

Let's assume that the distance of one lap around the circle is equal to 1 unit.

Given: - When Petya overtakes Vasya for the third time, Vasya has completed exactly 6 laps. - Both Petya and Vasya run at constant speeds.

To solve this problem, we can set up an equation based on the information given.

Let's say the speed of Petya is P units per lap, and the speed of Vasya is V units per lap.

When Petya overtakes Vasya for the third time, Petya has run 3 laps more than Vasya. Since Vasya has completed 6 laps, Petya has completed 6 + 3 = 9 laps.

Using the equation: Distance = Speed × Time, we can set up the following equation:

9P = 6V

Now, we need to find the ratio of the speeds of Petya and Vasya, which is P/V.

To find this ratio, we can divide both sides of the equation by V:

9P/V = 6

Therefore, the ratio of the speeds of Petya and Vasya is 9/6 = 3/2.

So, the speed of Petya is 1.5 times the speed of Vasya.