Question

винни пух и кенга в одно время вышли на тропинку между их домиками и направились друг к другу в гости.через 2 3 часа они встретились .каково расстояние между их домиками,если пух двигался со скоростью 30м.мин,а кенга в 10 раз быстрее???

Answer 1

23*30 = 690м Винни Пух

30*10 = 300 м/мин скорость Кенги

300*23 =6900м Кенга

6900+690 = 7590м расстояние домиками.

ОТВЕТ: 7590 м

Answer 2

23*30 = 690 (м) прошел Винни Пух

30*10 = 300 (м/мин) скорость Кенги

300*23 =6900 (м) прошла Кенга

6900+690 = 7590 (м) расстояние между их домиками. Это ответ

Answer 3

Question:

Winnie the Pooh and Kanga at the same time went out on a path between their houses and went to visit each other. After 2-3 hours they met. What is the distance between their houses if Pooh moved at a speed of 30m.min and Kanga 10 times faster?

Analysis:

* Winnie the Pooh and Kanga went out from their houses to visit each other * They met after 2-3 hours * Pooh's speed was 30m/min * Kanga's speed was 10 times faster than Pooh * Let's break this down step-by-step: ** Pooh's speed = 30m/min ** Kanga's speed = 10 * 30m/min = 300m/min ** Time taken = 2-3 hours = 120-180 minutes ** Pooh traveled: 30 * (120-180) = 3600-5400m ** Kanga traveled: 300 * (120-180) = 36000-54000m ** Let's take the minimum values: *** Pooh traveled: 3600m *** Kanga traveled: 36000m *** Total distance traveled by both = Pooh's distance + Kanga's distance = 3600 + 36000 = 39,600m ** Therefore, the distance between their houses is 39,600/2 = 19,800m