Question

Периметр прямоугольника =72см ,одна его сторона в 5 раз больше чему равна площадь пр. ?

Answer 1

Пусть одна из сторон прямоугольника - х см. Тогда другая - 5х(потому что одна сторона В 5 раз больше другой). а и b - стороны прямоугольника.
Р(периметр)=а+b+а+b=72
х+5х+х+5х=72
12х=72
х=6
S-площадь (a*b). 1 сторона - 6см, 2 сторона - 6*5=30см
S=6*30=180см^2
Ответ: 180 см^2

Answer 2

Perimeter of a Rectangle

To find the perimeter of a rectangle, we need to know the lengths of its sides. In this case, we are given that the perimeter of the rectangle is 72 cm, and one of its sides is 5 times larger than the other side.

Let's assume that the shorter side of the rectangle is represented by the variable 'x'. Since the longer side is 5 times larger, we can represent it as '5x'.

The formula for the perimeter of a rectangle is:

Perimeter = 2 * (Length + Width)

In this case, the length is '5x' and the width is 'x'. Substituting these values into the formula, we get:

72 = 2 * (5x + x)

Simplifying the equation:

72 = 2 * 6x

72 = 12x

Dividing both sides of the equation by 12:

x = 6

So, the shorter side of the rectangle is 6 cm, and the longer side is 5 times larger, which is 30 cm.

Area of the Rectangle

To find the area of the rectangle, we multiply the length and width of the rectangle. In this case, the length is 30 cm and the width is 6 cm.

Area = Length * Width

Area = 30 cm * 6 cm

Area = 180 cm²

Therefore, the area of the rectangle is 180 cm².

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