Question

Скорость пешехода равна 6 км / ч, что составляет три-одинадцетых скорости велосепедиста.С какой скоростью они сближаются , если движутся : а) навстречу друг-другу ;б)Велосепедист догоняет пешехода ?

Answer 1

Моё решение правильно 

Answer 2

1)12,5-6,2=6,3 км/ч  - скорость пешехода
2)12,5+6,3=18,8 км/ч - скорость сближения
Ответ: 18,8 км/ч

Answer 3

Speed of the Pedestrian and Cyclist

The speed of the pedestrian is given as 6 km/h, which is equal to three-elevenths (3/11) of the speed of the cyclist.

Let's calculate the speed of the cyclist first.

To find the speed of the cyclist, we can set up a proportion using the given information:

Speed of cyclist / Speed of pedestrian = 11/3

Simplifying the proportion, we find:

Speed of cyclist = (Speed of pedestrian) * (11/3) = 6 km/h * (11/3) = 22 km/h

Now that we know the speed of the cyclist is 22 km/h, we can proceed to answer the two questions.

a) When moving towards each other

When the pedestrian and the cyclist are moving towards each other, their speeds are added. Therefore, the relative speed at which they are approaching each other is:

Relative speed = Speed of pedestrian + Speed of cyclist

Substituting the given values, we have:

Relative speed = 6 km/h + 22 km/h = 28 km/h

Therefore, when moving towards each other, the pedestrian and the cyclist are approaching each other at a speed of 28 km/h.

b) When the cyclist overtakes the pedestrian

When the cyclist overtakes the pedestrian, the relative speed is the difference between their speeds. In this case, the cyclist is moving faster than the pedestrian. Therefore, the relative speed is:

Relative speed = Speed of cyclist - Speed of pedestrian

Substituting the given values, we have:

Relative speed = 22 km/h - 6 km/h = 16 km/h

Therefore, when the cyclist overtakes the pedestrian, they are approaching each other at a speed of 16 km/h.

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