Question

Первый моляр за 3 ч покрыл полы в комнате площадью 27 метров квадратных. Второй моляр, выполнял такую же работу, потратил на 2 ч больше, но площадь его комнаты была на 13 метров квадратных больше, чем у первого. У кого из них производительность больше и на сколько

Answer 1

1 маляр за 3ч-27м²
2 маляр-на 2 ч.больше t.и на 13м² больше  
1)3+2=5(ч)-2 маляр
2)27+13=40(м²)-2 маляр  
3)27:3=9(м²)-час  
4)40:5=8(м²)-час  
5)9-8=1(м²)-разница  
Ответ:на 1 м² разница между 1 и 2 маляром.

Answer 2

Calculation of Work Done by the First Molar

To solve this problem, we need to calculate the work done by the first molar and the second molar separately.

The first molar covered a floor area of 27 square meters in 3 hours. To calculate the work done, we can use the formula:

Work = Force × Distance

In this case, the force can be considered constant, so we can simplify the formula to:

Work = Force × Area

Since the area is given as 27 square meters, we can substitute it into the formula:

Work = Force × 27

However, we don't have the value of the force, so we cannot calculate the exact work done by the first molar without additional information.

Calculation of Work Done by the Second Molar

The second molar performed the same work but took 2 hours longer and covered an area that was 13 square meters larger than the first molar.

Let's assume the force exerted by the second molar is the same as the first molar. In that case, we can calculate the work done by the second molar using the same formula:

Work = Force × Area

The area covered by the second molar is given as 27 + 13 = 40 square meters. Substituting this value into the formula, we get:

Work = Force × 40

However, we also know that the second molar took 2 hours longer to complete the work. This means that the work rate (or productivity) of the second molar is lower than that of the first molar.

To compare the productivity of the two molars, we need to calculate the work rate, which is given by:

Work Rate = Work / Time

Let's assume the time taken by the first molar is T hours. In that case, the time taken by the second molar would be T + 2 hours.

Substituting the values into the formula, we get:

Work Rate of the First Molar = Work / T

Work Rate of the Second Molar = Work / (T + 2)

To determine which molar has a higher productivity, we need to compare the work rates of the two molars. However, without the exact values of the force and time taken by the first molar, we cannot calculate the work rates or determine which molar has a higher productivity.

Therefore, based on the given information, we cannot determine which molar has a higher productivity or by how much.

Please note that the given question seems to be a word problem, and the information provided is not sufficient to calculate the exact work rates or productivity of the molars.