Question

Запишите в виде равенства Один токарь выточил y деталий другой -на 7деталий больше чем первый а третий -на 8 деталий меньше чем второй . Вмести они сделали 81 деталь

Answer 1

Y+(y+7)+((y+7)-8)=81
y+y+7+y+7-8=81
3y+6=81
3y=81-6
y=(81-6)/3
y=25 - выточил первый токарь
25+7=32 -второй токарь
32-8=24 -третий токарь

Answer 2

Problem Analysis

We are given information about three turners who have produced a total of 81 parts. The second turner has produced 7 more parts than the first turner, and the third turner has produced 8 fewer parts than the second turner. We need to write an equation to represent this situation.

Writing the Equation

Let's assume that the number of parts produced by the first turner is represented by x.

According to the given information: - The second turner has produced 7 more parts than the first turner, so the number of parts produced by the second turner is x + 7. - The third turner has produced 8 fewer parts than the second turner, so the number of parts produced by the third turner is (x + 7) - 8.

The sum of the parts produced by all three turners is 81, so we can write the equation as: x + (x + 7) + ((x + 7) - 8) = 81.

Simplifying the equation: 3x + 6 = 81.

Solving the Equation

To solve the equation, we can subtract 6 from both sides: 3x = 75.

Then, divide both sides by 3: x = 25.

Answer

The first turner has produced 25 parts, the second turner has produced 25 + 7 = 32 parts, and the third turner has produced 32 - 8 = 24 parts.

Therefore, the equation representing the situation is x + (x + 7) + ((x + 7) - 8) = 81, and the solution is x = 25.