Question

Бросают 3 монеты и игральную кость. какова вероятность того, что выпадут три герба и шесть очков

Answer 1

 см. вложение

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Answer 2

P выпадения 3 орлов составляет 1/8

P выпадения 6 очков составляет 1/6

По комбинаторному правилу умножения надо перемножиить независящие друг от друга события, т.е. 1/8 * 1/6 = 1/48

Answer 3

Calculating the Probability

To calculate the probability of getting three heads and six points when tossing three coins and rolling a die, we need to consider the probabilities of each event separately and then multiply them together.

Let's break it down step by step:

1. Probability of getting three heads (H) when tossing three coins: - Since each coin has two possible outcomes (heads or tails), the probability of getting heads on one coin is 1/2. - To calculate the probability of getting three heads, we multiply the probabilities together: (1/2) * (1/2) * (1/2) = 1/8.

2. Probability of getting six points (6) when rolling a die: - A standard die has six sides, numbered from 1 to 6. - Each side has an equal probability of landing face up, so the probability of rolling a 6 is 1/6.

3. Probability of both events occurring together: - To calculate the probability of both events occurring together, we multiply the probabilities of each event: (1/8) * (1/6) = 1/48.

Therefore, the probability of getting three heads and six points is 1/48.