Question

С железнодорожной станции в 12 ч вышел скорый поезд со скорость 70 км/ч На 3 часа раньше с этой же станции был отправлен в том же направлении товарный поезд В 16 ч скорый поезд нагнал товарный Найдите скорость товарного поезда Решение

Answer 1

1)16-12=4(ч)- был в пути скорый поезд
2)70*4=280(км)-$ скорого поезда
3)4+3=7(ч)- был в пути товарный поезд
4)280:7=40( км/ч)- скорость товарного поезда

Answer 2

Problem Analysis

We are given that a fast train left a railway station at 12:00 PM with a speed of 70 km/h. Three hours earlier, a freight train was sent in the same direction from the same station. We need to find the speed of the freight train.

Solution

Let's assume the speed of the freight train is x km/h.

We know that the fast train caught up to the freight train at 4:00 PM. This means that the fast train traveled for 4 hours, while the freight train traveled for 7 hours (from 12:00 PM to 4:00 PM).

We can use the formula distance = speed × time to find the distance traveled by each train.

For the fast train: - Speed = 70 km/h - Time = 4 hours - Distance = 70 km/h × 4 hours = 280 km

For the freight train: - Speed = x km/h - Time = 7 hours - Distance = x km/h × 7 hours = 7x km

Since both trains traveled the same distance when they met, we can set up the equation:

280 km = 7x km

Now we can solve for x:

280 km / 7 = x km/h

x = 40 km/h

Therefore, the speed of the freight train is 40 km/h.

Answer

The speed of the freight train is 40 km/h.