Question

Из двух пунктов, расстояние между которыми 7 км 500 м, одновременно в одном направлении вышел пешеход со скоростью 6 км/ч и выехал автобус. Определите скорость автобуса, если он догнал пешехода через 15 минут.

Answer 1

15 мин = 0,25 часа 7 км 500 м = 7,5 км 6*0,25=1,5 км - прошёл пешеход 7,5+1,5=9 км - проехал автобус 9:0,25=36 км/ч - скорость автобуса

Answer 2

Problem Analysis

We are given that the distance between two points is 7 km 500 m. A pedestrian starts walking at a speed of 6 km/h in one direction, and a bus starts moving towards the pedestrian. We need to determine the speed of the bus if it catches up to the pedestrian in 15 minutes.

Solution

To solve this problem, we can use the formula:

Distance = Speed × Time

Let's denote the speed of the bus as v km/h.

The pedestrian walks for 15 minutes, which is equivalent to 15/60 = 0.25 hours.

The distance covered by the pedestrian is given by:

Distance_pedestrian = Speed_pedestrian × Time_pedestrian

Substituting the given values, we have:

Distance_pedestrian = 6 km/h × 0.25 h

Simplifying, we find:

Distance_pedestrian = 1.5 km

Since the bus catches up to the pedestrian, the distance covered by the bus is equal to the distance between the two points, which is 7 km 500 m.

Converting 500 m to km, we have:

Distance_bus = 7 km + 0.5 km

Simplifying, we find:

Distance_bus = 7.5 km

Now, we can set up the equation:

Distance_bus = Speed_bus × Time_bus

Substituting the known values, we have:

7.5 km = v km/h × 0.25 h

Simplifying, we find:

v km/h = 7.5 km / 0.25 h

Calculating, we find:

v km/h = 30 km/h

Therefore, the speed of the bus is 30 km/h.

Answer

The speed of the bus is 30 km/h.