Question

У двух мужиков 40 овец, а у одного меньше против другого на 6. Сколько у каждого?

Answer 1

У 1 мужика -  14 овец.
У 2 мужика - 26 овец.

Answer 2

1 мужик = х 
2 мужик = х-6
Всего = 40 овец
х+х-6=40
2х=40+6
2х=46
23 овец у первого мужика
у второго мужика 23-6=17 овец

Answer 3

Solution:

Let's solve this problem step by step.

1. Let's denote the number of sheep the first man has as x and the number of sheep the second man has as y.

2. We are given that the two men have a total of 40 sheep, so we can write the equation: - x + y = 40.

3. We are also given that one man has 6 fewer sheep than the other, so we can write the equation: - x = y + 6.

4. Now we can solve these two equations to find the values of x and y.

Substituting the value of x from the second equation into the first equation: - (y + 6) + y = 40 - 2y + 6 = 40 - 2y = 40 - 6 - 2y = 34 - y = 17.

Substituting the value of y back into the second equation: - x = 17 + 6 - x = 23.

Answer:

So, the first man has 23 sheep and the second man has 17 sheep.