Question

Собственная скорость катера в 10 раз больше скорости течение реки. за 5 часов катер прошел 90км пути против течерте реки. найти собственную скорость катера и реки

Answer 1

Пусть скорость течения х км/ч, тогда скорость катера 10х км/ч, Тогда скорость катера против течения 10х - х = 9х км/ч. Тогда 9х = 90 : 5. 9х = 18; х = 2 км/ч скорость течения. 2 * 10 = 20 км/ч скорость катера.

Answer 2

Problem Analysis

To solve this problem, we need to find the speed of the boat and the speed of the river current. We are given that the boat's speed is 10 times greater than the speed of the river current. Additionally, we know that the boat traveled 90 km against the current in 5 hours.

Solution

Let's assume the speed of the river current is x km/h. Since the boat's speed is 10 times greater than the speed of the river current, the speed of the boat can be represented as 10x km/h.

We are given that the boat traveled 90 km against the current in 5 hours. This means that the effective speed of the boat against the current is the difference between the boat's speed and the speed of the river current. Therefore, we can set up the following equation:

90 km = (10x km/h - x km/h) * 5 hours

Now, let's solve this equation to find the value of x.

Calculation

Simplifying the equation, we have:

90 km = (10x - x) km/h * 5 hours

90 km = 9x km/h * 5 hours

Dividing both sides of the equation by 5 hours, we get:

90 km / 5 hours = 9x km/h

18 km/h = 9x km/h

Dividing both sides of the equation by 9, we find:

18 km/h / 9 = x km/h

2 km/h = x km/h

Therefore, the speed of the river current is 2 km/h.

Since the speed of the boat is 10 times greater than the speed of the river current, the speed of the boat is:

10 * 2 km/h = 20 km/h

Hence, the speed of the boat is 20 km/h and the speed of the river current is 2 km/h.

Answer

The speed of the boat is 20 km/h and the speed of the river current is 2 km/h.