Question

Решите срочно!!!!!!!!!!!!!!!!!!!!5а+10=20 (7-х) +2=8 4(х+3)=9 12-(х-3)=9 10(1+х) =40 (4+х) -5=1 1 3- _а=2 3 1 _а+5=12 2 (2х+1/0,5=10 Дополнение в первой простой дроби три - одна вторая = два

Answer 1

2
1
0.75
6
3
2
Больше я не успеваю.

Answer 2

5а+10=20
5а= 10
а = 2

(7-х)+2= 8
7-х= 6
-х= -1
х=1

4(х+3)=9
4х+12=9
4х= -3
х= -3/4

Answer 3

Solving the Equations

Let's solve the given set of equations step by step.

1. 5a + 10 = 20 + (7 - x) - Subtract 10 from both sides: 5a = 10 + (7 - x) - Subtract 7 from both sides: 5a - 7 = 10 - x - Rearranging: x = 10 - 5a + 7 [[1]](https://archive.org/stream/kvant-journal/Kvant1992_djvu.txt).

2. 2 = 8 + 4(x + 3) - Subtract 8 from both sides: -6 = 4(x + 3) - Divide by 4: -1.5 = x + 3 - Subtract 3 from both sides: x = -4.5.

3. 9 + 12 - (x - 3) = 9 - Combine like terms: 21 - x + 3 = 9 - Simplify: 24 - x = 9 - Subtract 24 from both sides: -x = 9 - 24 - Simplify: -x = -15 - Multiply by -1: x = 15.

4. 10(1 + x) = 40 - Expand: 10 + 10x = 40 - Subtract 10 from both sides: 10x = 30 - Divide by 10: x = 3.

5. (4 + x) - 5 = 1 + 1 - Combine like terms: 4 + x - 5 = 2 - Simplify: x - 1 = 2 - Add 1 to both sides: x = 3.

6. 3 - 1/a + 2/a = 2 - Combine like terms: 3 + 1/a = 2 - Subtract 3 from both sides: 1/a = -1 - Invert both sides: a = -1.

7. Дополнение в первой простой дроби три - одна вторая = два - This appears to be a language-specific question. The translation is required for further analysis.

Conclusion

The solutions to the given equations are as follows: - a = -1 - x = 3 - x = 15 - x = -4.5 - x = 3 - x = 10 - 5a + 7

If you need further assistance or have more questions, feel free to ask!