Question

Два контролёра готовой продукции совместно за 1 час работы проевряют 500 деталей.С какой производителтностью работает каждый контролёр если производительность первого на 20 дет./ч меньше чем второго?

Answer 1

20:2=10
500:2=250
250-10=240(дет./ч) 1 контролер
250+10=260(дет./ч) 2 контролер
Ответ:240 дет./ч, 260 дет./ч.

Answer 2

Calculating the Efficiency of Each Controller

To calculate the efficiency of each controller, we can use the given information that two controllers jointly inspect 500 parts in 1 hour. Additionally, we know that the efficiency of the first controller is 20 parts per hour less than the second controller.

Let's denote: - Efficiency of the first controller as x parts per hour - Efficiency of the second controller as (x + 20) parts per hour

We can set up the following equation based on the given information: x + (x + 20) = 500

Solving for x will give us the efficiency of the first controller, and (x + 20) will give us the efficiency of the second controller.

Calculating the Efficiency

Let's solve the equation: 2x + 20 = 500

Subtracting 20 from both sides: 2x = 480

Dividing by 2: x = 240

So, the efficiency of the first controller is 240 parts per hour.

The efficiency of the second controller is (240 + 20) = 260 parts per hour.

Therefore, the first controller works at an efficiency of 240 parts per hour, while the second controller works at an efficiency of 260 parts per hour.