Question

С 3-ех лугов собрали 19,7т. С 1-ого и 2-ого лугов собрали сена одинаково, а с 3-его собрали на 1,1 т >, чем те. Сколько сена собрали с каждого луга. РЕШИТЬ УРАВНЕНИЕМ!!!

Answer 1

1) пусть с 1 и 2 собрали по х т сена, тогда с 3  (х+1,1) т.    

 или ( 2х +1,1) если  :  а с 3-его собрали на 1,1 т >, чем те ОЗНАЧАЕТ  а с 3 собрали на 1,1 т больше , чем с 1и2 вместе !!!

составим уравнение

х + х +(х+1,1)=19,7               или   х +х+(2х+1,1)=19,7

3х=18,6                                             4х=18,6

х=6,2 -собрали с 1и2                    х=4,65-собрали с 1и2  

х+1,1 =7,3 -собрали с 3                х+1,1=5,75 - собрали с 3

 

Answer 2

Problem Analysis

We are given the following information: - Three meadows collected a total of 19.7 tons of hay. - The first and second meadows collected the same amount of hay. - The third meadow collected 1.1 tons more hay than the other two meadows combined.

We need to determine how much hay was collected from each meadow.

Solution

Let's assume the amount of hay collected from each of the first two meadows is x tons.

According to the given information, the third meadow collected 1.1 tons more hay than the other two meadows combined. Since the first two meadows collected the same amount of hay, the total amount of hay collected from the first two meadows is 2x tons. Therefore, the amount of hay collected from the third meadow is 2x + 1.1 tons.

The total amount of hay collected from all three meadows is 19.7 tons. So we can write the equation:

x + x + (2x + 1.1) = 19.7

Simplifying the equation:

4x + 1.1 = 19.7

4x = 18.6

x = 4.65

Therefore, each of the first two meadows collected 4.65 tons of hay, and the third meadow collected 2 * 4.65 + 1.1 = 10.4 tons of hay.

Answer

The amount of hay collected from each meadow is as follows: - The first meadow: 4.65 tons - The second meadow: 4.65 tons - The third meadow: 10.4 tons