Question

Найти наименьшее число которое при делении на 2,3,4,5 и 6 дает в остатке 1, а на 7 делится нацело???

Answer 1

Наверное это число 301
Если остаток при делении на (2,3,4,5,6) единица то искомое число можно найти умножая число 7 на число оканчивающееся на 3
301:7=43 
а при делении на 2,3,4,5,6 дает в остатке 1

Answer 2

Finding the Smallest Number

To find the smallest number that, when divided by 2, 3, 4, 5, and 6, leaves a remainder of 1, and is divisible by 7, we can use the Chinese Remainder Theorem. This theorem states that if we have a system of simultaneous congruences, we can find a unique solution modulo the product of the moduli under certain conditions.

The smallest number that satisfies these conditions is 301.

This number satisfies the given conditions because: - When divided by 2, 3, 4, 5, and 6, it leaves a remainder of 1. - It is divisible by 7.

The Chinese Remainder Theorem can be used to solve this problem, and the smallest number that satisfies the given conditions is 301.

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