Question

Два самолёта летели с одинаковой скоростью. Один самолёт был в воздухе 5 часов, а другой - 8 часов и пролетел на 2505 км больше, чем первый. Сколько км пролетел первый самолёт? Заранее спасибо!

Answer 1

Какое расстояние пролетел каждый из самолетов?
1.1600:(5-3)=800 (км.ч)
2.800*3=2400 км. пролетел один самолет
3.800*5=4000 км пролетел другой самолет

Answer 2

Problem Analysis

We are given two airplanes flying at the same speed. One airplane flies for 5 hours, while the other flies for 8 hours and covers a distance that is 2505 km greater than the first airplane. We need to determine the distance covered by the first airplane.

Solution

Let's assume that the speed of both airplanes is x km/h.

The distance covered by the first airplane can be calculated using the formula: distance = speed × time.

For the first airplane, the distance covered is x km/h × 5 hours.

For the second airplane, the distance covered is x km/h × 8 hours.

According to the problem, the second airplane covers a distance that is 2505 km greater than the first airplane. Therefore, we can set up the following equation:

x km/h × 8 hours = (x km/h × 5 hours) + 2505 km

Now, let's solve this equation to find the value of x.

Calculation

To solve the equation, we can simplify it as follows:

8x = 5x + 2505

Subtracting 5x from both sides:

3x = 2505

Dividing both sides by 3:

x = 835

Therefore, the speed of both airplanes is 835 km/h.

Now, we can calculate the distance covered by the first airplane:

Distance = Speed × Time = 835 km/h × 5 hours = 4175 km

So, the first airplane covered a distance of 4175 km.

Answer

The first airplane covered a distance of 4175 km.

Please let me know if you need any further assistance!