Question

Из двух станций ,расстояние между которыми равно 531,76км.вышлиодновременнонавстречудруг другудва поезда.Встретились через 3,4 ч.найдите скорость каждого поезда,если известно, что скорость одногоиз них в1,3 раза больше скорости другого. помогите пожалуйста решить

Answer 1

Скорость первого х, второго 1,3х. Первый до встречи прошёл 3,4х км, второй 1,3х*3,4, что равно 531,76-3,4х.
Имеем уравнение: 4,42х=531,76-3,4х     7,82х=531,76           х=68 км/час
Скорость второго 1,3*68 = 88,4 км/час

Answer 2

Problem Analysis

We have two trains that start simultaneously from two stations and meet each other after 3.4 hours. The distance between the two stations is 531.76 km. We need to find the speed of each train, given that the speed of one train is 1.3 times the speed of the other train.

Solution

Let's assume the speed of the slower train is x km/h. Therefore, the speed of the faster train will be 1.3x km/h.

We can use the formula speed = distance / time to find the speeds of the trains.

The slower train covers the entire distance between the two stations in 3.4 hours, so its speed is:

x = distance / time = 531.76 km / 3.4 hours The faster train covers the same distance in the same time, but at a speed of 1.3 times that of the slower train:

1.3x = distance / time = 531.76 km / 3.4 hours Now we can solve these equations to find the values of x and 1.3x.

Calculation

Let's calculate the speeds of the trains:

x = 531.76 km / 3.4 hours = 156.7 km/h 1.3x = 1.3 * 156.7 km/h = 203.71 km/h

Therefore, the speed of the slower train is 156.7 km/h and the speed of the faster train is 203.71 km/h.

Answer

The speed of the slower train is 156.7 km/h and the speed of the faster train is 203.71 km/h.

Please let me know if you need any further assistance!