Question

В магазине имеется крупа трёх видов гречка перловка и рис всего 580 кг .если бы продали 44 кг гречки 18 кг перловки и 29 кг риса то масса круп всех видов стало бы одинаковой. сколько кг крупы каждого вида имеется в магазине.

Answer 1

580-(44+18+29)=489 - поровну всего
489:3=163 поровну каждого
163+44=207 гречки
163+18=181 перловки
163+29=192 риса

Answer 2

Problem Analysis

We are given that there are three types of grains in a store: buckwheat, pearl barley, and rice. The total weight of all the grains is 580 kg. If we sell 44 kg of buckwheat, 18 kg of pearl barley, and 29 kg of rice, the weight of all the grains would be the same. We need to determine how much of each type of grain is in the store.

Solution

Let's assume the weight of buckwheat is x kg, the weight of pearl barley is y kg, and the weight of rice is z kg.

According to the given information, we have the following equations:

1. x + y + z = 580 (equation 1) - The total weight of all the grains is 580 kg. 2. (x - 44) + (y - 18) + (z - 29) = (x + y + z) - (44 + 18 + 29) (equation 2) - If we sell 44 kg of buckwheat, 18 kg of pearl barley, and 29 kg of rice, the weight of all the grains would be the same.

Let's solve these equations to find the values of x, y, and z.

From equation 2, we can simplify it as follows: x + y + z - 44 - 18 - 29 = x + y + z - 91 -44 - 18 - 29 = -91 -91 = -91

This means that equation 2 is always true, regardless of the values of x, y, and z. Therefore, equation 2 does not provide any additional information to solve the problem.

We can now solve equation 1 to find the values of x, y, and z.

x + y + z = 580

Let's solve this equation using a method called substitution.

From equation 1, we can express x in terms of y and z: x = 580 - y - z

Substituting this value of x in equation 1, we get: (580 - y - z) + y + z = 580 580 - z = 580 z = 0

Now, substituting the value of z = 0 in equation 1, we get: x + y + 0 = 580 x + y = 580

Since we have two variables (x and y) and one equation, we cannot determine the exact values of x and y. However, we can express one variable in terms of the other.

Let's express y in terms of x: y = 580 - x

Therefore, the weight of buckwheat (x) can be any value between 0 and 580 kg, and the weight of pearl barley (y) is equal to 580 minus the weight of buckwheat.

To summarize: - The weight of buckwheat (x) can be any value between 0 and 580 kg. - The weight of pearl barley (y) is equal to 580 minus the weight of buckwheat. - The weight of rice (z) is 0 kg.

Please note that the given information does not allow us to determine the exact weights of each type of grain in the store. We can only provide the possible range of values based on the given conditions.

I hope this helps! Let me know if you have any further questions.