Question

1) 3-2(u-1)>8+u2) 5(u+2)+14<6-u

Answer 1

1) Раскроем скобки
3-2*u+2>8+u
Приведем подобные
-3*u>3
u<-1
2) Раскроем скобки
5*u+10+14<6-u
Приведем подобные
6*u<6-24
u<-3

Answer 2

1) 3 - 2(u - 1) > 8 + u 3 - 2u + 2 > 8 + u 5 - 2u > 8 + u 5 - 8 > 2u + u -3 > 3u u < -1

2) 5(u + 2) + 14 < 6 - u 5u + 10 + 14 < 6 - u 5u + 24 < 6 - u 5u + u < 6 - 24 6u < -18 u < -3

So the solution to the system of inequalities is u < -1 and u < -3. Therefore, the solution is u < -3.