Question

Пуля массой 10 грамм пробивает стену скорость пули при этом уменьшилась от 800 до 400 метров в секунду Найдите изменение импульса пули

Answer 1

dp=m*V1-m*V2=m*(V1-V2)=0,01*(800-400)=4 кг*м/с

Answer 2

Calculation of Change in Bullet's Impulse

To calculate the change in impulse of a bullet, we need to use the formula:

Change in impulse = Final impulse - Initial impulse

The impulse of an object is given by the product of its mass and velocity. In this case, the bullet has a mass of 10 grams (0.01 kg) and its velocity changes from 800 m/s to 400 m/s.

Let's calculate the initial and final impulses of the bullet:

Initial impulse = mass * initial velocity = 0.01 kg * 800 m/s

Final impulse = mass * final velocity = 0.01 kg * 400 m/s

Now we can calculate the change in impulse:

Change in impulse = Final impulse - Initial impulse

Change in impulse = (0.01 kg * 400 m/s) - (0.01 kg * 800 m/s)

Calculating this expression gives us the change in impulse of the bullet.