Question

Периметр треугольника авс равен 82 см сторона ав меньше стороны вс на 8 см и больше стороны ас на 4 см длина стороны вс равна

Answer 1

X+x+8+x-4=82
3x=82-8+4
3x=78
X=78:3

X=26
AB=26, BC=26+8=34, ac=26-4=22

Answer 2

The question is about finding the length of the side BC of a triangle ABC, given the perimeter and some relations between the sides. The answer is 34 cm, and here is how to find it:

- Let x be the length of the side AB in cm. Then, according to the question, the length of the side BC is x + 8 cm, and the length of the side AC is x - 4 cm. - The perimeter of the triangle is the sum of the lengths of the sides, so we have:

$$x + (x + 8) + (x - 4) = 82$$

- Simplifying the equation, we get:

$$3x + 4 = 82$$

- Subtracting 4 from both sides, we get:

$$3x = 78$$

- Dividing both sides by 3, we get:

$$x = 26$$

- Therefore, the length of the side AB is 26 cm, the length of the side AC is 26 - 4 = 22 cm, and the length of the side BC is 26 + 8 = 34 cm.

This is the same answer as given in the first web search result. You can also check the other results for more explanations and examples . I hope this helps you understand the problem and the solution.